Question

In this question-Q 4 Draw ΔPQR in which QR = 5 cm, ∠Q = 40° and PR = 6 cm we use the criteria SAS where the angle is included but in the question it asks to make PR as 6 cm so then the angle won't be included. Is it correct or not

Answer 1

Here is ur answer...

Steps of constructions:

Steps of constructions:(1) Draw seg QR of length 4.2 cm.

Steps of constructions:(1) Draw seg QR of length 4.2 cm.(2) Draw ray QT such that ∠RQT=40

Steps of constructions:(1) Draw seg QR of length 4.2 cm.(2) Draw ray QT such that ∠RQT=40 ∘

Steps of constructions:(1) Draw seg QR of length 4.2 cm.(2) Draw ray QT such that ∠RQT=40 ∘

Steps of constructions:(1) Draw seg QR of length 4.2 cm.(2) Draw ray QT such that ∠RQT=40 ∘ (3) Mark point S on ray QT such that QS=8.5cm

Steps of constructions:(1) Draw seg QR of length 4.2 cm.(2) Draw ray QT such that ∠RQT=40 ∘ (3) Mark point S on ray QT such that QS=8.5cm(4) Draw seg RS.

Steps of constructions:(1) Draw seg QR of length 4.2 cm.(2) Draw ray QT such that ∠RQT=40 ∘ (3) Mark point S on ray QT such that QS=8.5cm(4) Draw seg RS.(5) Construct the perpendicular bisector of seg RS.

Steps of constructions:(1) Draw seg QR of length 4.2 cm.(2) Draw ray QT such that ∠RQT=40 ∘ (3) Mark point S on ray QT such that QS=8.5cm(4) Draw seg RS.(5) Construct the perpendicular bisector of seg RS.(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.

Steps of constructions:(1) Draw seg QR of length 4.2 cm.(2) Draw ray QT such that ∠RQT=40 ∘ (3) Mark point S on ray QT such that QS=8.5cm(4) Draw seg RS.(5) Construct the perpendicular bisector of seg RS.(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.(7) Draw seg PR.Therefore, ΔABC is the required triangle

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