Question

In this reaction 2Al+3/2O2 formed Al2O3 ,9 gm of Al will react with how many gm of O2?

Answer 1

The correct answer is 8gO2. The chemical reaction is 2 Al(s) + 3/2 O2(g)===è Al2 O3(s).

to easily solve the problem, you need to convert from mass to moles and hence use stoichiometric relationships to determine the moles of O2.

The oxygen molar mass to find the mass of O2 need 9gAl (1molAl/26.98gAl)(32molO2/2molAl)(32.00gO2/1molO2) = 8gO2.

Answer 2

$\huge \tt 8g \: \: of \: \: { \: }^{ \huge O} { 2}^{ \: }$