Question

in this triangle AB=24cm, BC=10cm , O is the center of the circle. B angle is 90 , then op=?​

Answer 1

Answer:

OP is 4 cm

Step-by-step explanation:

In the figure, constructing OQ & OR perpendicular to BC and AB.

So, PC=QC, BQ=BR, AR=AP

{Tangents from any point are equal.}

Let PC be x.

AP=26-x

BQ=10-x

AR=14+x

As, AP=AR

14+x=26-x

2x=12

x=6 cm

So, BQ=4 cm

In quadrilateral ORBQ, 3 angles are 90° and BR & BQ are equal.

So, it is a square.

Sides of a square are equal.

So, radius of circle = BQ = 4

Therefore, OP=4 cm