Question

in this triangle DE||BC, AD=4cm, DB=6cm and AE=6cm Then the value of EC is​

Answer 1

Answer:

7.5cm

Step-by-step explanation:

Given DE∥BC

∴△ADE∼△ABC

Thus, by property of similar triangles,

ABAD=ACAE

∴AD+DBAD=AE+ECAE

∴4+64=5+EC5

∴104=5+EC5

∴4(5+EC)=50

∴20+4EC=50

∴4EC=30

∴EC=7.5cm

Answer 2

Answer:

Step-by-step explanation:

Given DE∥BC

∴△ADE∼△ABC

Thus, by property of similar triangles,

$\frac{AD}{AB}$ = $\frac{AE}{AC}$

$\frac{AD}{AD+DB} =\frac{AE}{AE+EC}$

$\frac{4}{4+6} =\frac{6}{6+EC}$

$\frac{4}{10} =\frac{6}{6+EC}$

24 + 4EC = 60

4EC = 60-24

4EC = 36

EC = 9

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