Question

in this way 32 in to fours division that they are in A.P and 1st & 4th of product and 2nd & 3rd of product in ratio of 7:15 become. .plz solve anybody else

Answer 1

Let the 4 numbers in AP be a-3d,a+d,a-d,a+3d.   ---- (1)

Given that Sum of 4 terms = 32

                  a - 3d + a + d + a - d + a + 3d = 32

                              4a = 32 

                                a = 8.

Substitute a = 8 in (1) we get, (8-3d),(8+d),(8-d),(8+3d).

Given that 1st and 4th product = 2nd and 3d product in the ratio of 7:15.

                   (8 - 3d) * (8 + 3d) / (8 + d) * (8 - d) = 7/5

                   d = +2 (or) - 2.

Substitute d = 2 in (1), we get

a - 3d = 8 - 3(2) = 2

a - d = 6

a + d = 10

a + 3d = 8 + 3(2) = 14.


Hope this helps!