In this we have to find current through 4 ohm resistor
Answers
Answer :
First of all we need to find equivalent resistance of the circuit.
[Refer to the attachment 1 and 2]
Equivalent resistance = 25Ω
★ As per ohm's law, current flow through a conductor is directly proportional to the potential difference V = IR
Net current flow in circuit,
➠ V = IR
➠ 25 = I(25)
➠ I = 1 A
We have to find current through 4Ω resistor. So, firstly we will find potential drop across 4Ω resistor and then we will apply ohm's law.
[Refer to the third attachment]
★ Potential at point B :
⭆ V(A) - V(B) = 5(I)
⭆ 25 - V(B) = 5(1)
⭆ V(B) = 25 - 5
⭆ V(B) = 20V
★ Potential at point C :
⭆ V(B) - V(C) = 8I₁
⭆ 20 - V(C) = 8(0.5)
⭆ V(C) = 20 - 4
⭆ V(C) = 16V
★ Potential at point E :
⭆ V(B) - V(E) = 10I₂
⭆ 20 - V(E) = 10(0.5)
⭆ V(E) = 20 - 5
⭆ V(E) = 15V
★ Current through 4Ω resistor :
➙ V(C) - V(E) = 4I'
➙ 16 - 15 = 4I'
➙ I' = 1/4
➙ I' = 0.25 A
Cheers!
Answer:
First of all we need to find equivalent resistance of the circuit.
Equivalent resistance = 25Ω
As per ohm's law, current flow through a conductor is directly proportional to the potential difference.. V = IR
Net current flow in circuit,
➠ V = IR
➠ 25 = I(25)
➠ I = 1 A
We have to find current through 4Ω resistor. So, firstly we will find potential drop across 4Ω resistor and then we will apply ohm's law.
Potential at point B :
⭆ V(A) - V(B) = 5(I)
⭆ 25 - V(B) = 5(1)
⭆ V(B) = 25 - 5
⭆ V(B) = 20V
Potential at point C :
⭆ V(B) - V(C) = 8I₁
⭆ 20 - V(C) = 8(0.5)
⭆ V(C) = 20 - 4
⭆ V(C) = 16V
Potential at point E :
⭆ V(B) - V(E) = 10I₂
⭆ 20 - V(E) = 10(0.5)
⭆ V(E) = 20 - 5
⭆ V(E) = 15V
Current through 4Ω resistor :
➙ V(C) - V(E) = 4I'
➙ 16 - 15 = 4I'
➙ I' = 1/4
➙ I' = 0.25 A
