In thr Rhombus ABCD, AB=4cm and <BCD=60. Find the diagonal BD
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In the Rhombus ABCD ,
The diagonal BD is 4 cm .
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Given: AB=4cm and ang BCD=60
To Find: The diagonal BD
Solution:
- Let the intersecting diagonal be O,
- So then, considering the triangle OBC,
cos 60= OB/BC
- Applying values of cos 60 and solve further,
1/2 = OB/4
OB = 2cm
Now, OB + OD = DB,
(its one of the diagonals)
- Putting values of OB and OD,
2+2=DB
DB = 4cm
Answer:
- Db is equal to 4 cm.
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