In three different families there are respectively 3 boys and 2 girls, 2 boys and 3 girls, 4 boys and 1 girl. A family is selected at random and from it 2 children are taken at random, the probability that both are boys is
Answers
Answered by
3
Answer:
= 13
32
Step-by-step explanation:
ANSWER
Let:
Group A: 3 girls, 1 boy
Group B: 2 girls, 2 boys
Group C: 1 girl, 3 boys
The combination of 1 girl and 2 boys can be selected in:
(i) A - girl, B - boy, C - boy: 4 3 × 4 2 × 4 3
= 64 18
(ii) A - boy, B - girl, C - boy: 4 1 × 4 2 × 4 3
= 64 6
(iii) A - boy, B - boy, C - girl: 4 1 × 4 2 × 4 1
= 64 2
Hence, required probability = 18 + 6 + 2
64 64 64
= 26
64
= 13
32
HOPE THIS HELPS
Similar questions