Question

In three numbers, the first is twice the second and thrice the third, If the average of these three numbers is 44, then the first number is?​

Answer 1

Answer:

72

Step-by-step explanation:

Lets assume be the first number is 6 then secod number would be 3 and third would be 2 according to condition....and they are in the ratio of 6:3:2 so there would be one common multiple for all..lets find that common multiple. thus we know that the average is 44.. that means we can say that (

(6x+3x+2x)/3=44 where x is the common multiple

then,

6x+3x+2x=132

11x =132

x=12, which is common multiple..

so firtst number would be 12*6=72

Your answer is 72

similarly second number would be 3*12=36

and third 2*12=24

you can cross verify,

(72+36+24)/3,

132/3.

44

:)

Answer 2

Answer:

let the first number = x

let the secondnumber=y

let the third number = z

The first is twice the second and thrice the third number and average be =44 ---------GIVEN

so

x= 2x+ 3x =5X

= 5x + y+ z = 44

x+ y+ z= 44/5

the first number be 8.8