Question

in three termed arithmetic progresion, the middle term is 30. Then sum of end terms is​

Answer 1

Answer:

60

Step-by-step explanation:

Let the required AP be a - d, a, a + d.

Given, middle term = 30   ⇒ a = 30

Hence,

   sum of end terms:

⇒ (a - d) + (a + d)

⇒ a - d + a + d

⇒ 2a

⇒ 2(30)

⇒ 60

    Hence, the sum of end terms is 60

Answer 2

Given :- in three termed arithmetic progression, the middle term is 30. Then sum of end terms is ?

Solution :-

Let the given three terms of AP are (a - d) , a and (a + d)

where (a - d) and (a + d) are end terms and a is middle term .

so,

→ Middle term = 30 (given)

→ a = 30 ---- Eqn.(1)

then,

→ sum of end terms = ?

→ (a - d) + (a + d)

→ a + a - d + d

→ 2a

putting value of Eqn.(1)

→ 2 * 30

→ 60 (Ans.)

Hence, sum of end terms is 60 .

Learn more :-

evaluate the expression given by 83 - 81 + 87 - 85 +__________ + 395 - 393 + 399 - 397

https://brainly.in/question/14081691

If the nth term of an AP is (2n+5),the sum of first10 terms is

https://brainly.in/question/23676839