In tina's new class there are 55 students. This is 1.25 times the number of students in her old class. How many students were there in her old class
Answers
Step-by-step explanation:
ANSWER
Given , N=55,n(M)=23,n(P)=24,n(C)=19,n(M∩P)=12,n(P∩C)=7,n(M∩C)=9,n(M∩P∩C)=4
Now, number of students studying only Mathematics
n(M∩P
′
∩C
′
)=n(M)−n(M∩P)−n(M∩C)+n(M∩P∩C) (by Venn diagram)
=23−9−12+4=6
Now, number of students studying only Physics
n(P∩M
′
∩C
′
)=n(P)−n(P∩M)−n(P∩C)+n(P∩M∩C) (by Venn diagram)
=24−12−7+4=9
Now, number of students studying only Chemistry
n(C∩M
′
∩P
′
)=n(C)−n(C∩M)−n(C∩P)+n(M∩P∩C) (by Venn diagram)
=19−9−7+4=7
So, the number of people who study exactly one of the three subjects =6+9+7=22
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Answer:
44
Step-by-step explanation:
Let the number of students in her old class be x.
ATQ,
x * 1.25 = 55
=> x = 55/1.25
=> x = 44.
.°. the number of students in her old class was 44.
Hope it helps you.