Question

In tirangle PQR PT perpendicular to QR such that triangle PQT ~ triangle RQP then angle QPR? ​

Answer 1

Answer:

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Answer 2

Triangle PQT ~ triangle RQP then angle QPR:

Step-by-step explanation:

In ΔPQR , PT⊥QR and ΔPQR≈ΔRQP

∠PTR=∠PTQ (each 90°)

PQ=PR (Given)

PQ=QR (Common side)

Thus, △PQT≅△RQP

Hence, ∠PQT=∠PQR (By CPCT)  or, PT bisects ∠QPR