Question

in titration 15 ml of 0.1 M HCl Neutrlies 25 ml of CA(OH)2 what is the molarity of Ca(OH)2 ?

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Answer 1

Explanation:

0.06M

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Answer 2

Answer:

0.006M

Explanation:

as using formula

MCaOH = nCaOH /VCaOH

molarity = moles of solute per liter of solution

M = n/ V(L)

hence n is mass in gm per molecular weight

there fore as the equationis

in titration 15 ml of 0.1 M HCl Neutrlies 25 ml of CA(OH)2 what is the molarity of Ca(OH)2 ?

solution

MCaOH2 = nCaOH divided by VCaOH

VCaOH is 25ml i.e. 0.025L

and from the equation

nCaOH is equal to the nHCL

therefore

nHCL =MHCL * VHCL (M is molecular weight)

nHCL = 0.1M *0.015L= 0.00015 mol

hence

MCaOH = nCaOH / VCaOH

= 0.00015 mol / 0.025L = 0.006 M