in traiangle ABC if AB=BC and angle b is70 find angle A
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Answer:
Given: In a Δ ABC, AB = AC and ∠B = 70° ∠B = ∠C [Angles opposite to equal sides are equal] Therefore, ∠B = ∠C = 70° Sum of angles in a triangle = 180° ∠A + ∠B + ∠C = 180° ∠A + 70° + 70° = 180° ∠A = 180° – 140° ∠A = 40°
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Answer:
angle A = 55°
Step-by-step explanation:
since, angles opposite to equal sides are equal
angle A = angle C = let x°
according to angle sum property of triangle
angle A + angle B + angle C = 180°
x+70+x= 180°
2x = 110°
x= 55°
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