In traiangleb ABC, mass of 100 g, located on point A, mass of 200 g located on point C and mass of 150 g is located at point B, they are kept in y-plane, find the coordinate of centre of mass of triangle ABC
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With the x- and y- axes chosen as shown in Fig., the coordinates of points O, A and B forming the equilateral triangle are respectively (0,0),(0.5,0),(0.25,0.25
3
). Let the masses 100g,150g and 200g be located at O, A and B be respectively. Then,
X=
m
1
+m
2
+m
3
m
1
x
1
+m
2
x
2
+m
3
x
3
=
(100+150+200)g
100(0)+150(0.5)+200(0.25)gm
=
450
75+50
m=
450
125
m=
18
5
m
Y=
450g
100(0)+150(0)+200(0.25
3
)gm
=
450
50
3
m =
9
3
m=
3
3
1
m
The centre of mass C is shown in the figure. Note that it is not the geometric centre of the triangle OAB.
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