Math, asked by disha349360, 7 months ago

in traingle ABC, AB=AC=15 and BC=18 find cos of angle ABC and sin of angle ACB​

Answers

Answered by rohit8289
2

Answer:

sin angle ACB = 15 by 18

cos angle ABC = 18 by 15

Step-by-step explanation:

opposite side AB 15 sin ACB= -------------------- = ------ = -----

hypotenuse BC 18

adjacent side BC 18

cos ABC= --------------------- = ------ = ------

hypotenuse AB 15

HOPE IT HELPS YOU

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