Question

IN TRAINGLE ABC ANGLE A = 120,FIND ANGLE B AND ANGLE C IF AB= AC

Answer 1

∠A=120

AB=AC

∴∠B=∠C =x (angles opp. to equal sides are equal)

now,

∠A+∠B+∠C=180 ( angle sum property)

120+x+x=180

2x=60

x=30

∴∠B=30 & ∠C=30

hope it helps

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Answer 2

Answer:

given  AB=AC

∠A =120°

CONSTRUCTION: draw AD ⊥ BC

so, BD=DC

now in Δ ADB

∠D= 90°

∠A= 60° (AD is perpendicular to BC So angle A = 120/2)

now ∠A + ∠D +∠B = 180°(angle sum property of triangle)

60°+90°+∠B=180°

∠B = 180°-150°

∠B=30°

similarly we can prove for Δ ADC

⇒∠B=∠C= 30°

HOPE ITS HELPFUL!!!!!

Step-by-step explanation: