in traingle ABC, angle A = theta and angle B = 90. If sec theta = 1+t²/t² and t is greater than 0 but smaller than 1. Show that sin theta + cos theta = 1
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Given theta lies in first quadrant costheta>0 tantheta = 1√(5) As we know that sec^2 theta = 1 + tan^2 theta = 1 + (1√(5))^2 = 1 + 15 = 65 sectheta ...
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the question is not correct please correct it
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