In traingle ABC, angle bac=90,ad perpendicular bc,
DE perpendicular ab
Prove
AE x AB=BD x DC
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here in triangle abc bc square = AC + AB square
in tri adc = AC =AD +DC SQUARE
IN TRI ADB= BA = AD +BD SQUARE
THE LENGHT OF AE IS EXACTLY HALF SO and even BD AND DC
HENCE 1.5 +1.5
THEREFORE PROVED THAT AE X AB=BD X DC
Step-by-step explanation:
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