In traingle ABC if AB=AC and angleA = 80degree then find the value of angleB and angleC
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Let the other angles be x
sum of three angles of a triangle= 180°
80 + x + x = 180
80+2x= 180
2x = 180-80
2x= 100
x= 100÷2x
x= 50°
therefore, angle b = 50°
angle c = 50°
sum of three angles of a triangle= 180°
80 + x + x = 180
80+2x= 180
2x = 180-80
2x= 100
x= 100÷2x
x= 50°
therefore, angle b = 50°
angle c = 50°
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if ab equals to ac then b and c are equal first substrate 180-80 equals to then divide by 2 it's 50 now b and c are 50
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