In traingle abc the lengths of the two larger sides are 10and 9units respectively if the angles are in
a.P then the length of the third side can be
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let a1= 10 units
and, a2=9
therefore d=a2-a1
=>10-9
d=-1
an= a+(n-1)d
a3= 10+(3-1)-1
=> 10+(2)-1
=> 10-2
=> 8
Therefore the third side can be 8units
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