Question

in traingle abc the measure of angle a is more by 40 then the sum of the measure of triangle b triangle c also the ratio of measure of triangle b and c is 4.:3 then find the measure of angles of the triangles​

Answer 1

Answer:

angle b+angle c+40=angle a

again b/c=4/3

3b=4c

again , a+b+c=180

=> b+c+40+b+c=180

=> 2(b+c)=180-40

=> b+c=140/2

=> b+c=70

=> 3b+3c=70×3=210

=> 4c+3c=210

=> 7c=210

=> c=210/7

=> c=30

3b=4c

=> 3b=4.30

=> b=4.30/3

=> b=40

a=b+c+40=40+30+40=110

so, a=110 , b= 40 , c= 30