Question

in traingle PQR, PQ= 5√3 PR=10 cm, QR 5cm find m angel P

a) 45 degree
b) 60 degree
c) 307 degree​

Answer 1

Answer:

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Answer 2

Given:

in triangle PQR, PQ= 5√3 PR=10 cm, QR 5cm find m angel P

Step-by-step explanation:

Use Pythagoras theorem,

$\[\begin{array}{l} \Rightarrow {10^2} = {\left( {5\sqrt 3 } \right)^2} + {5^2}\\ \Rightarrow 100 = 75 + 25\\ \Rightarrow 100 = 100\end{array}\]$

Therefore the triangle PQR is a right angled triangle  and right angled at Q.

Refer the image given below,

$\[\begin{array}{l} \Rightarrow \tan p = \frac{{5\sqrt 3 }}{5}\\ \Rightarrow \tan p = \sqrt 3 \\ \Rightarrow \tan p = \tan 60^\circ \\ \Rightarrow \angle p = 60^\circ \end{array}\]$

Hence, the measure of the angle p is $\[60^\circ \]$.