Question

in trangle ABC, AB=3x,BC=4x,CA=5x and the perimeter of the triangle is 72cm.The value of x is​

Answer 1

Step-by-step explanation:

3x + 4x + 5x = 72

12x = 72

x = 6cm

Answer 2

GIVEN :-

• In Triangle ABC, AB = 3 cm , BC = 4x cm AC = 5x cm .
• Perimeter of Triangle = 72 cm

TO FIND :-

• The value of x.

SOLUTION :-

$\setlength{\unitlength}{1.8cm}\begin{picture}\thicklines\put(8,1){\line(1,0){3}}\put(8,1){\line(1,1){1.5}}\put(11,1){\line(-1,1){1.5}}\put(8,1){\line(1,1){1.5}}\put(8.6,1.8){\sf{3x}}\put(10.3,1.8){\sf{4x}}\put(9.4,0.75){\sf{</u><u>5x</u><u>}}\put(9.4,2.6){\bf {A}}\put(7.8,1){\bf {B}}\put(11,1){\bf {C}}\put(10.2,2.2){\boxed{\sf{@prince5132}}}\end{picture}$

▪︎Perimeter = sum of all the sides

=> 72 cm = AB + BC + AC

=> 72 = 3x + 4x + 5x

=> 72 = 12x

=> x = 72/12

=> x = 6

Hence the value of x is 6.

Hence, AB = 3 × 6 = 18 cm

BC = 4 × 6 = 24 cm

AC = 5 × 6 = 30 cm

VERIFICATION :-

=> Perimeter = sum of all the sides

=> 72 cm = 18 cm + 24 cm + 30 cm

=> 72 cm = 72 cm

L.H.S = R.H.S

HENCE VERIFIED