In trangleABC,AB=20cm<A=30°,AC=12cm find the pwrpandicular distance from c to AB
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ABC is triangle angle A= 30°
now by applying trigonometric ratio
sin 30° = opposite side ÷ hypothenuse
1/2 = perpendicular / 12
perpendicular of the triangle form C to AB = 6cm
now by applying trigonometric ratio
sin 30° = opposite side ÷ hypothenuse
1/2 = perpendicular / 12
perpendicular of the triangle form C to AB = 6cm
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