Question

In tranglePQR, angleQ = 90°, angleR = and if tan theta=8/15,
find sin theta
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given that:

QP=8cm,PR=6cm and SR=3cm

(I) In △PQR and △SPR

∠PRQ=∠SRP (Common angle)

∠QPR=∠PSR (Given that)

∠PQR=∠PSR (Properties of triangle )

∴△PQR∼△SPR (By AAA)

(II)

$\frac{pq}{sp} = \frac{qr}{pr} = \frac{pr}{sr}$

(Properties of similar triangles)

⇒SP8cm=3cm6cm

⇒SP=4cm and 

⇒6cmQR=3cm6cm

⇒QR=12cm

(III)

ar(△SPR)ar(△PQR)=SP2PQ2=4282=4