Question

In transferring 2.5C charge through a wire 10J of work if needed . Find the potential difference across the wire

Answer 1

Answer:

Potential difference (v) = work done /charge

Here,w=10J

Q=2.5C

Putting in the formula,

V=4 volt

That sit..

Explanation:

Answer 2

Solution :

⏭ Given:

✏ Magnitude of charge = 2.5C

✏ Work needed to move charge = 10J

⏭ To Find:

✏ Potential difference across the wire

⏭ Formula:

✏ Relation between Work, Charge and potential difference is given by

$\star \: \underline{ \boxed{ \bold{ \sf{ \pink{ \large{W = q \triangle{V}}}}}}} \: \star$

⏭ Terms indication:

• W denotes work
• q denotes charge
• ΔV denotes p.d.

⏭ Calculation:

$\implies \sf \: W = q \times \triangle{V} \\ \\ \implies \sf \: \triangle{V} = \frac{W}{q} \\ \\ \implies \sf \: \triangle{V} = \dfrac{10}{2.5} \\ \\ \implies \: \underline{ \boxed{ \bold{ \sf{ \large{ \orange{ \triangle{V} = 4 \: Volt}}}}}} \: \gray{ \bigstar}$