In trapezium ABCD. AB = 4 cm, BC = DC = 10 cm and AB IDC. Find the area of trapezium
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1
Answer:
56
Step-by-step explanation:
de =dc-ab
= 10-4
= 6
be =√10^2 -6^2
= √100-36
= √64
= 8
area area of trapezium=1/2*sum of parallel side* hight
1/2*(10+4)*8
1/2*14*8
7*8
56
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2
Step-by-step explanation:
now we have height
trapezium area= 1/2 × sum of parallel sides × height
=1/2×(4+10)×8
=1/2×14×8
=1×7×8
=56cm^2
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