In trapezium ABCD, AB||CD, AB-3CD. Diagonal AC & BD intersect in pointO. Prove that OB-30D & OA=30C
Answers
Answered by
0
Answer:
Correct option is
B
9:1
In △AOB & COD
∠AOB=∠COD ...Given
∠OAB=∠OCD ...Given
∠OBA=∠ODC ...Given
△AOB∼△COD ...by AAA test of similarity
By theorem on ratio of areas of similar triangles,
A(△COD)
A(△AOB)
=(
CD
AB
)
2
A(△COD)
A(△AOB)
=(
1
3
)
2
=
1
9
Similar questions