Question

In trapezium ABCD, AB || DC. Diagonals AC and BD intersects each other in point O. IfOA = 2x + 7, OB = 4x, OD = 4x - 4 and OC = 2x+4, then find'x'.​

Answer 1

Answer:

First we have to draw a diagram of trapezium

[]ABCD

Then draw a diagonal . Where Intersection of diagonal give name it point O

Then write OA = 2x + 7, OB = 4x, OD = 4x - 4 and OC = 2x+4

Then Show ∆ AOB and ∆COD Similar

then OA/OC = OB/OD

= 2x + 7/2x + 4 = 4x/4x - 4

= 2x + 7 ( 4x - 4 ) = 4x ( 2x + 4 )

= 8x² - 8x + 28x - 28 = 8x² + 16x

8x² get cancelled

= - 8x + 28x - 28 = 16x

= 20x - 28 = 16x

= 20x - 16x = 28

= 4x = 28

= x = 28/4

= x = 7

Therefore , the value of 'x' is 7