Question

In trapezium abcd ab is parallel to dc seg bd is perpendicular to ad and seg ac perpendicular to bc given ad =15, bc=15 and ab=25 find area of trapezium

Answer 1

Sin bac = 15/25

 

<bac = 36.87

 

Cos bad = 15/25

 

<bad = 53.13

 

<cad = <bac - <bad

 

        = 53.13 – 36.87

 

        = 16.26

 

Ac = root (25^2 – 15^2) = 20

 

Area of abc = ½ x 15 x 20 = 150

 

Area of adc = ½ x ac x ad Sin <cad = ½ x 20 x 15 Sin 16.26

                     = 42

 

Total area = 150 + 42

 

                  = 192

Answer 2

Answer:

Step-by-step explanation:

Sin bac = 15/25

<bac = 36.87

Cos bad = 15/25

<bad = 53.13

<cad = <bac - <bad

= 53.13 – 36.87

= 16.26

Ac = root (25^2 – 15^2) = 20

Area of abc = ½ x 15 x 20 = 150

Area of adc = ½ x ac x ad Sin <cad = ½ x 20 x 15 Sin 16.26

= 42

Total area = 150 + 42

= 192