Math, asked by ashi9273, 1 year ago

in trapezium ABCD ab parallel to dc is equal to 30 cm BC is equal to 15 CM BC is equal to 44 and ad is equal to 13 find the area of trapezium

Answers

Answered by minnionlover
7
HEYA MATE


HERE IS YOUR ANSWER

Translate D by vector AB, and let its image be E. Quadrilateral ABED is a parallelogram, so EB is equal in length to DA. Now consider triangle EBC. All three sides are known. 

EB = 13 cm 
BC = 15 cm 
CE = 14 cm 

Use Heron's formula. For triangles that is. There is no Heron's formula for quadrilaterals. 

(13 + 15 + 14)/2 = 21 

area(EBC) = √[21(21 - 13)(21 - 15)(21 - 14)] 
= √[21(8)(6)(7)] 
= √(7056) 
= 84 

Let EC be the base of that triangle. Find its corresponding height. 

(base)(height)/2 = area 
14h/2 = 84 
h = 12 

The height of triangle EBC is 12 cm. That is also the height of the trapezium. 

area(ABCD) = (AB + DC)h/2 
= (30 + 44)(12)/2 
= 444 cm² 



HOPE THIS HELPS YOU

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Answered by kpnutiyalseri
3

Answer: In this question BC is 44 or 15 cm.......????????


Step-by-step explanation:



ashi9273: 15
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