Question

In trapezium ABCD,AD is parallel to BC diagonals AC and BD intersect at point O. AD=10cm BC=20cm area of triangle AOB=3sqcm find the area of trapezium ABCD ?​

Answer 1

Answer:

Given, trapezium ABCD, AD=20, ∠A=60 degree

Draw perpendicular from D on AB, which meets AB at E

Now, In △ADE,

sin60 degree= DE/AD

SQUARE ROOT 3/2=DE/AD

DE=10 square of 3

DE = 17.32 cm