Question

In trapezium ABCD as shown AB//DC, AD=DC=BC=20cm and (ii) distance btw AB and DC ​

Answer 1

ab is a trapezius and dc is also a rhibous

distance between ab and dc is 30 cm

Answer 2

Answer:

Given, trapezium ABCD, AD=20, ∠A=60∘

Draw perpendicular from D on AB, which meets AB at E

Now, In △ADE,

sin60° = DE/AD

√3/2 = DE/AD

DE = 10√3

DE = 17.32 cm

Hope it helps u❣❣✌️......

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