In trapezium ABCD, C=102 find all the remaining angles of the trapezium
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x+x+102+x=360
3x=360-102
x=258/3
x=86
angle A=86
angle B=86
angle C=102
angle D=86
3x=360-102
x=258/3
x=86
angle A=86
angle B=86
angle C=102
angle D=86
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