Question

in trapezium ABCD if a b is equal to 1 by 3 CD and area of triangle ABC is equal to 21 cm find the area of triangle COD help me​

Answer 1

Answer:

Step-by-step explanation:

AB||CD

AB=1/3 (CD)

IN TRIANGLE AOB & TRIANGLE COD

ANGLE ABO= ANGLE CDO

(ALTERNATE INTERIOR ANGLE)

ANGLE BAO= ANGLE DCO (SAME)

ANGLE AOB= ANGLE COD

(VERTICALLY OPPOSITE ANGLE)

SO TRIANGLE AOB IS CONGRUENT TO TRIANGLE COD

(AREA AOB)/(AREA COD)= (AB^2)/(CD^2)

21/ COD = (AB)^2/9AB^2

21/COD= AB^2/9AB^2

21/COD=1/9

AREA TRIANGLE COD =21×9= 189CM^2

Answer 2

Step-by-step explanation:

area of triangle cod =189 cm ^2