Math, asked by asmakhan10, 1 year ago

In trapezium ABCD, side AB || side PQ || side DC, AP=15, PD=12,QC=14, find BQ​

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Answered by SRK1729
58

if the parallel intersects trapezium it divides its side of intersection in same proportion

so , ap/dp = bq/qc

15/12 = BQ/14

5/4 = BQ/14

5/2 = BQ/7

BQ = 35/2

BQ =17.5

Answered by harshdeep1273
27

(Theorem : If a line parallel to a side of a triangle intersects the remaining sides in two distinct points, then the line divides the sides in the same proportion.)

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