In trapezium ABCD, side AB || side PQ || side DC, AP=15, PD=12,QC=14, find BQ
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if the parallel intersects trapezium it divides its side of intersection in same proportion
so , ap/dp = bq/qc
15/12 = BQ/14
5/4 = BQ/14
5/2 = BQ/7
BQ = 35/2
BQ =17.5
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(Theorem : If a line parallel to a side of a triangle intersects the remaining sides in two distinct points, then the line divides the sides in the same proportion.)
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