In trapezium ABCD with AB parallel to CD if,angle A is 100 then angle D is equal to
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80........because AB is parallel to CD
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Angle D is equal to 80°.
Given,
ABCD is a trapezium. AB║CD.
∠A = 100°
To Find,
Angle D.
Solution,
For AB║CD with transversal AD.
The Sum of interior angles must be equal to 180°.
⇒ ∠A + ∠D = 180°
⇒ 100° + ∠D = 180°
⇒ ∠D = 180° - 100°
⇒ ∠D = 80°
Hence, angle D is equal to 80°.
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