Question

In traveling a distance of 525m the velocity of a body changes from 45m/s to 60m/s calculate its acceleration

Answer 1

According to the third equation of motion,
v^2=u^2 + 2as
Therefore
60^2=45^2+2a*525
a will come 1.5m/s^2

Answer 2

a = (v^2 - u^2)/(2S)
= (60^2 - 45^2) / (2 * 525)
= 1.5 m/s^2