Physics, asked by KrishnaCR, 5 hours ago

in travelling a distance of 525m the velocity of body changes from 45m-1 to 60m-1 calculate it's acceleration briefly​

Answers

Answered by sp998279123
1

Answer:

Acceleration = 1.53m/^2

Explanation:

Given: V = 60m/s^2,  U = 45m/2^2, Acceleration = ?

V^2 - U^2 = 2as (3rd kinematic equation)

60^2 - 45^2 = 2 * a * 525                => 3600 - 2025/1050

=> 1575/1050            => 1.5m/s^2 = Acceleration

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