Question

in trepaziium ABCD AB parrelal CD
ifAB = 30 cm ,BC =17 cm, CD = 20 cm and DA =9 cm,what is its Area ?​

Answer 1

Step-by-step explanation:

trapezium ABCD

AB∥CD,

AB=30cm and CD=44cm, AD=13cm,BC=15cm.

semi-perimeter =

2

30+44+13+15

=51

area of trapezium =

(s−a)(s−b)(s−a−c)(s−a−d)

⋅

(b−a)

(a+b)

where a and b are two parallel sides and b > a and c and d are non-parallel sides

s=

2

a+b+c+d

=51

area of trapezium ABCD=

44−30

30+44

⋅

(51−30)⋅7(51−30−13)⋅(51−30−15)

=

14

74

⋅

21⋅7⋅8⋅6

=

7

37

⋅7

3⋅3⋅2⋅8

=37×3×4=37×12=444cm 2