in tri ABC AB=5 BD=3 DC=4 find the lenght of AC
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AB sq = AD sq + BD sq
5 sq = AD sq + 3 sq
25 = AD sq + 9
AD sq = 25 - 9
AD sq = 16
AD = 4
Now, we can find AC also by Pythagoras theorem.
AC sq = AD sq +DC sq
AC sq = 16 + 16
AC sq = 32
AC = 5.12(approximately)
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