Question

in tri. ABC if a =18 b = 24 c= 30 then find the value of a(tri.ABC) and tanA​

Answer 1

S=a+b+c/2

S=18+24+30/2

S=72/2

S=36

a=18

b=24

c=30

using this formula

$\sqrt{s(s - a)(s - b)(s - c)}$

=

$\sqrt{36(36 - 18)(36 - 24)(36 - 30) } \\ \sqrt{36(18)(12)(6) }$

=6×2×3×3×2

=216