Math, asked by 555kadividedby, 1 year ago

in tri ABC the bisector of interior angle A meets BC in D. The bisector of exterior angle A meets bc produced in E. PROVE THAT:- BD:BE=CD:CE. HINT: for the bisector of angle A which is exterior of tri BAC, AB:AC=BE:CE. please give the proof?....................

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Answered by Nandini2885

0

pic plzz it would be easy to understand

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