Math, asked by adarsh1952aj, 11 months ago

in triange ABC if AB = 6√3 cm AC =12cm and BC= 6cm find angles A and B​

Answers

Answered by 18shreya2004mehta
5

Answer:

As,

(6√3)2 + 62 = 122

⇒ AB2 + BC2 = AC2

i.e. sides of the triangle ABC satisfy the Pythagoras theorem

(Hypotenuse)2 = (base)2 + (Perpendicular)2

∴ ABC is a right-angled triangle with hypotenuse as AC

Now,

By converse of 30°-60°-90° triangle theorem i.e.

In a right-angled triangle, if one side is half of the hypotenuse then the angle

opposite to that side is 30°.

∠A = 30°

Answered by wwwmanthan272005
3

Step-by-step explanation:

12^2=144

6^2+6√3^2=144

therefore angle b=90

in an rt. angled triangle if one side is half of hypotenuse then the angle opposite to that side is 30

angle a=30

Similar questions