in triange ABC if AB = 6√3 cm AC =12cm and BC= 6cm find angles A and B
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Answered by
5
Answer:
As,
(6√3)2 + 62 = 122
⇒ AB2 + BC2 = AC2
i.e. sides of the triangle ABC satisfy the Pythagoras theorem
(Hypotenuse)2 = (base)2 + (Perpendicular)2
∴ ABC is a right-angled triangle with hypotenuse as AC
Now,
By converse of 30°-60°-90° triangle theorem i.e.
In a right-angled triangle, if one side is half of the hypotenuse then the angle
opposite to that side is 30°.
∠A = 30°
Answered by
3
Step-by-step explanation:
12^2=144
6^2+6√3^2=144
therefore angle b=90
in an rt. angled triangle if one side is half of hypotenuse then the angle opposite to that side is 30
angle a=30
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