In Triangel ABC, AD is the bisector of BAC and is perpendicular to the side
BC. Find the values of x and y.
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if AD is angle bisector and also perpendicular to BC then ,
∆BAD≈∆CAD ...(RHS criteria)
=> x-1 = 2x-5 (CPCT)
=> x = 4
also, 2x = 5y -2 ( CPCT)
=> 2×4 = 5y-2
=> 5y = 10
=> y = 2
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Answer:
x=4 and y=2
Step-by-step explanation:
In the ΔABD and Δ ACD
AD is common
∠ADB = ∠ADC=90
∠BAD = ∠CAD
Thus ΔABD ≅ Δ ACD
So BD=CD
x-1=2x-5, x=4
Also AB=AC
Thus 2x=5y-2
2*4=5y-2
5y=10 Or y=2
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