Question

in triangke ABC If angle A =70° and AB=AC find angle b​

Answer 1

Answer:

this is the answer

Step-by-step explanation:

Step-by-step explanation:

Given In ∆ABC ,

AB=AC and <B=70°

/* In ∆ABC , If AB=AC then <C=<B */

Given \: \angle C=\angle B=70\degreeGiven∠C=∠B=70°

\angle A+\angle B+\angle C=180\degree∠A+∠B+∠C=180°

\implies \angle A+70 \degree+70 \degree=180 \degree⟹∠A+70°+70°=180°

\implies \angle A+140\degree=180 \degree⟹∠A+140°=180°

\implies\angle A=180\degree-140 \degree⟹∠A=180°−140°

\implies \angle A=40 \degree⟹∠A=40°

Therefore,

\angle A=40 \degree∠A=40°

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Answer 2

Answer:

Angle B is 55°.

Step-by-step explanation:

If AB = AC then Triangle ABC is Isosceles.

If AB = AC then Triangle ABC is Isosceles.Therefore, Angle B = Angle C

If AB = AC then Triangle ABC is Isosceles.Therefore, Angle B = Angle CLet Angle B = Angle C = x

If AB = AC then Triangle ABC is Isosceles.Therefore, Angle B = Angle CLet Angle B = Angle C = x We know that sum of interior angles of a triangle is 180°.

If AB = AC then Triangle ABC is Isosceles.Therefore, Angle B = Angle CLet Angle B = Angle C = x We know that sum of interior angles of a triangle is 180°.So, 70°+2x = 180°

If AB = AC then Triangle ABC is Isosceles.Therefore, Angle B = Angle CLet Angle B = Angle C = x We know that sum of interior angles of a triangle is 180°.So, 70°+2x = 180°=> 2x = 110°

If AB = AC then Triangle ABC is Isosceles.Therefore, Angle B = Angle CLet Angle B = Angle C = x We know that sum of interior angles of a triangle is 180°.So, 70°+2x = 180°=> 2x = 110°=> x = 55°

If AB = AC then Triangle ABC is Isosceles.Therefore, Angle B = Angle CLet Angle B = Angle C = x We know that sum of interior angles of a triangle is 180°.So, 70°+2x = 180°=> 2x = 110°=> x = 55°Therefore Angle B is 55°.

If AB = AC then Triangle ABC is Isosceles.Therefore, Angle B = Angle CLet Angle B = Angle C = x We know that sum of interior angles of a triangle is 180°.So, 70°+2x = 180°=> 2x = 110°=> x = 55°Therefore Angle B is 55°.Mark as brainliest