Math, asked by sam200749, 3 months ago

In triangl ABC, angle A =x+18 , angle B =2(x-12) angle C = 3x/2 - 3 . Find each angle of the triangle and hence show that it is an equilateral triangle.​

Answers

Answered by VEDESWARITS
1

Answer:

Answer: since all angles A, B, C are equal to 60 degree, the triangle is equilateral.

Step-by-step explanation: 180 = sum of all angles of the triangle sum = angle A + angle B + angle C 180 = (x + 18) + - 24) + 3[x/2 -1] 180 = X + 18 + - 24 + - 3 180 = X + + + 18 - 24 - 3

180

180

180/9= 1

20

+ 1 =

= x

x = 42

angle A = x + 18 angle B = - 24 angle C = 3[x/2 -1]

= 42+18 = (2*42) - 24

= 3[42/2 - 1]

= 60 84 — 24

= 3[21 - 1]

= 60

= 20

= 60

Step-by-step explanation:

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Answered by dandi19
0
Equilateral triangle has equal angles which is 60. Therefore, it is equal to 180 degrees.

Add the angles: A + B + C

(x + 18) + 2(x - 12) + [(3/2)x - 3] = 180

x + 18 + 2x - 24 + 3x/2 - 3 = 180

x + 2x + 3x/2 = 180 - 18 + 24 + 3

x + 2x + 3x/2 = 189

2[x + 2x + 3x/2 = 189]

2x + 4x + 3x = 378

9x = 378

x = 42

Substituting the value of x

x + 18 = 42 + 18 = 60 degrees

2x - 24 = 2(42) - 24 = 60 degrees

3x/2 - 3 = 3(42)/2 - 3 = 60 degrees


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