Math, asked by radheshamdhumale25, 6 months ago

in triangle 90degree angle b=90 BC=5 ac -ab=1 ​

Answers

Answered by st6531779
1

Answer:

If angle B= 90 degree BM perpendicular to AC ,BC = 5 cm and AC = 12 CM then the ratio of areas of ∆ BMC and ∆ABC 25 : 144. Since the ratio of the area of two similar triangles is equal to the square of ratio of their corresponding sides. Thus, the ratio of areas of ∆ BMC and ∆ABC is 25:144.

Answered by sankeanuradha
1

If angle B= 90 degree BM perpendicular to AC ,BC = 5 cm and AC = 12 CM then the ratio of areas of ∆ BMC and ∆ABC 25 : 144. Since the ratio of the area of two similar triangles is equal to the square of ratio of their corresponding sides. Thus, the ratio of areas of ∆ BMC and ∆ABC is 25:144.

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