In triangle ab=ac and angle acd =120 find bac
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Question:
In fig.,AB=AC and ∠ACD=120°.Find ∠A.
Answer:
We have,
AB=AC
➙∠B=∠C. [∵Angles opposite to equal sides are equal]
Now,∠ACB+∠ACD=180°. [Angles of a linear pair]
➙ ∠C+120°=180°
➙ ∠C=60°
➙ ∠B=60°. [∵∠B=∠C]
Using angle sum property in ∆ABC,we obtain
∠A+∠B+∠C=180°
➙ ∠A+60°+60°=180°. [∠B=∠C=60°]
➙ ∠A=60°
Step-by-step explanation:
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